-10x^2+17x-3=0

Solution for -10x^2+17x-3=0 equation:

-10x^2+17x-3=0

a = -10; b = 17; c = -3;
Δ = b2-4ac
Δ = 172-4·(-10)·(-3)
Δ = 169
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{169}=13$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(17)-13}{2*-10}=\frac{-30}{-20}
=1+1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(17)+13}{2*-10}=\frac{-4}{-20}
=1/5
$